8.5 formation of Binary ionic compounds
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Lattice Energy
- The change in energy that takes place when separated gaseous ions are packed together to form an ionic solid
- Often described as the energy released when an ionic solid forms from its ions
- Ex: M+(g) + X-(g) à MX(s)
- Energy is a state function
- Energy change is exothermic(-)
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Determining the heat of formation for a substance
- Ex: Use the following data to estimate ∆HfO for sodium chloride
- Na(s) + ½ Cl2(g) --> NaCl(s)
- Lattice energy -786 kJ/mol
- Electron affinity(Cl) -348 kJ/mol
- Ionization energy (Na) 495 kJ/mol
- Bond energy (Cl2) 239 kJ/mol
- Heat sublimation: ∆Hsub Na 108 kJ/mol
- Na(s) à Na(g) is sublimation 108kJ/mol
- Na(g) --> Na+(g) is ionization 495 kJ/mol
- ½ Cl2(g) --> Cl(g) is breaking a bond and only have half a mole so 239/2 kJ/mol
- Cl(g) --> Cl-(g) is electron affinity -348 kJ/mol
- Na+(g) + Cl-(g) --> NaCl(s) is lattice energy -786 kJ/mol
- Sum the heats and reactions:
- Na(s) + 1/2Cl2(g) --> NaCl(s) -412kJ/mol
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Calculating lattice energy
- Calculate the lattice energy of KBr from the following equations
- K(s) + ½ Br2(g) --> KBr(s)
- ∆H sub (K) 90 kJ/mol
- Bond energy (Br2) 112 kJ/mol
- Ionization energy (K) 419 kJ/mol
- Electron affinity (Br) -325 kJ/mol
- ∆HfO KBr(s) -392 kJ/mol
- Do same thing as last example only this time unknown is lattice energy
- K(s) --> K(g) 90 kJ/mol
- K(g) --> K+(g) 419 kJ/mol
- ½ Br2(g) --> Br(g) 112 kJ/mol
- Br(g) --> Br-(g) -325 kJ/mol
- K+(g) + Br-(g) --> KBr(s) unknown
- K(s) + 1/2Br2(g) --> KBr(s) -392 kJ/mol
- Answer: -632 kJ/mol
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Lattice energy continued
- Lattice energy = k(Q1*Q2/r)
- Where k is a proportionality constant that depends on the structure of the solid and the electron configs of the ions
- Q’s are the charges of the ions
- r is the shortest distance between the centers of the cations and anions
- Note: when you have opposite charges the sign is negative as expected since it is an exothermic process
- Process is more exothermic as the ionic charges increase and as the distance between the ions in the solid decrease.
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